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Compare 2 Hashes in Ruby

I have 2 hashes like this:
hash1 = {“1″=>”foo”, “2”=>”bar”, “3”=>”baz”, “4”=>”qux”}
hash2 = {“5″=>”foo”, “3”=>”baz”, “4”=>”qux”}

And both hashes have the same keys.
I need to compare them and if any key is not present in hash1, add it to hash1.
So in the example above hash1 will be:
{“1″=>”foo”, “2”=>”bar”, “3”=>”baz”, “4”=>”qux”, “5”=>”foo”}

Is there any way to do this?

A:

You could do:
hash1.merge(hash2) do |key, old_value, new_value|
if!hash1[key]
hash1[key] = new_value
end
end

(This is only safe if the new value is only ever nil and has the same type of class as the first value)

A:

If you want the effect of a set union, and you’re using Ruby >= 2.1:
hash1.merge(hash2).values_at(*hash1.keys).select {|_,v| v!= nil}

If you want a Hash.new:
hash1.merge(hash2).reject {|_,v| v.nil?}

To get a “set difference” (if you’re not concerned about creating extra values), just select the keys that are present in hash2 and delete them from hash1, e.g.
hash1.reject {|_,v| hash2.include? v}

If you’re using Ruby
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